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Question: 2HCl+2KI+NaOCl—> I2+NaCl+H2O+2KCl I2+2Na2S2O3–> 2NaI+Na2S4O6

by | Nov 28, 2023 | questions




2HCl+2KI+NaOCl—> I2+NaCl+H2O+2KCl

I2+2Na2S2O3–> 2NaI+Na2S4O6
Question: 2HCl+2KI+NaOCl—> I2+NaCl+H2O+2KClI2+2Na2S2O3–> 2NaI+Na2S4O6

Show transcribed image text a. Suppose you did an exploratory titration and 2.00 mL of the bleach took 4.60 mL of Na2S203(aq). How many mL of bleach would you use to end up needing 25-40 mL of Na2S203(aq)? Round this to the nearest mL due to pipet sizes available. Show work. b. What is the molarity of NaOCI in a solution of bleach if 10.00 mL requires 22.35 mL of 0.02191 M Na2S203 to reach the endpoint? Show work. Hint work through the 12 first. Ans. 0.02448 M

a. Suppose you did an exploratory titration and 2.00 mL of the bleach took 4.60 mL of Na2S203(aq). How many mL of bleach would you use to end up needing 25-40 mL of Na2S203(aq)? Round this to the nearest mL due to pipet sizes available. Show work. b. What is the molarity of NaOCI in a solution of bleach if 10.00 mL requires 22.35 mL of 0.02191 M Na2S203 to reach the endpoint? Show work. Hint work through the 12 first. Ans. 0.02448 M

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