For a standard normal random variable Z, and a normal random
variable X with mean 6 and variance 9 determine the following
probabilities.

a.) P(Z < -.80) (Give decimal answer to four places past
decimal, without the leading zero.)

b.) P(-.80 ? Z ? 1.23)    (Give decimal answer to
four places past decimal, without the leading zero.)

c.) P(Z > 1.75)    (Give decimal answer to
four places past decimal, without the leading zero.)

d.) P(X < 3)    (Give decimal answer to four
places past decimal, without the leading zero.)

e.) P(3 < X < 9) (Give decimal answer to four places past
decimal, without the leading zero)